Wet Feet; 2013-10-17 10:52; 6; As the title states, I am trying to use gsub where I use a vector for the "pattern" and "replacement". https://www.datasciencemadesimple.com/sub-gsub-function-in-r grepl returns a logical vector (match or not for each element of x). mimetype A regular expression to filter files based on their MIME types, e.g., '^text/' for plain text files. For sub and gsub a character vector of the same length as the original. Actualmente, tengo un código que se ve así: R: gsub, patrón = vector y reemplazo = vector Como dice el título, estoy t r atando de usar gsub donde uso un vector para el “patrón” y “reemplazo”. I leave it as an exercise to figure out why not. Gsub a every element after a keyword in R, gsub function replaces all matches of a string, if the parameter is a string vector, returns a string vector of the same length and with the same attributes (after possible coercion to character). Multiple gsub. I don't now whether or not this is less "kludgy" than the explicit loop (loops are implicitly used anyway), but Reduce(function(x1,x2)gsub(x2,"something else",x1),x, init=y) does it using gsub. While grep() and grepl() were used to simply check whether a regular expression could be matched with a character vector, sub() and gsub() take it one step further: you can specify a replacement argument. In this post you learned how to select numerics from a character string array in the R programming language. Note, however, that this will **not** work if the "something else" regular expression itself contained elements of x in the "wrong" order. sub & gsub R Functions; Extract Substring Before or After Pattern; Find Position of Character in String; The R Programming Language . For sub and gsub return a character vector of the same length and with the same attributes as x (after In case you have further questions, don’t hesitate to let me know in the comments section below. sub and gsub perform replacement of the first and all matches respectively. :/ Marianne-- grep, grepl, regexpr, gregexpr and regexec search for matches to argument pattern within each element of a character vector: they differ in the format of and amount of detail in the results. I tried looking at the different apply()s but am not getting anywhere, partly because I lack the mental flexibility to combine the fact that I am applying gsub() to y but now want to apply that to x ... erm. A vector of filename extensions (without the leading periods). grep(value = TRUE) returns a character vector containing the selected elements of x (after coercion, preserving names but no other attributes). multigsub - A wrapper for gsub that takes a vector of search terms and a vector or single value of replacements.. sub_holder - This function holds the place for particular character values, allowing the user to manipulate the vector and then revert the place holders back to the original values. y <- gsub(x[i],"something else",y)} Surely, there must be a less kludgy way? R: gsub, pattern = vector and replacement = vector. For regexpr an integer vector of the same length as text giving the starting position of the first match, or -1 if there is none, with attribute "match.length" giving the length of the matched text (or -1 for no match).

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