However only three measurements are allowed. You must figure out which. "There are 12 men on an island. 12 men live on an island. That person is the heavier (or lighter). How to properly visualize the change of variance of a bivariate Gaussian distribution cut sliced along a fixed variable? There is also a see-saw on the island. The ice cube and the basketball have the same weight. The best answers are voted up and rise to the top, Not the answer you're looking for? You can weigh three combinations of men on the see-saw. Bottom line? Death by roo roo. Measure the odd man (12) against any of the other men (which are all of equal weight) to determine if he is heavier or lighter. -v, 1 split the 12 islanders into three groups What are the consequences of overstaying in the Schengen area by 2 hours? c) If they are the same, then one of 3,4 is different. Thus we need to log224 bits of information to solve the puzzle. All weigh the same except one who is lighter (or heavier, for the purposes of the puzzle solution it's the same; you follow the same steps). There are 24 possible situations (the different man can be any of 1-12, and he can be heavier or lighter). {{#media.media_details}} {{#media.focal_point}}, First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. There is an island with 12 islanders. Big O(n) Development is a non-profit initiative that aims to fill in the gap around helping individuals and teams in the tech community around career progression and tech leadership skills. L: sit on the left, R: sit on the right, -: don't sit on the seesaw.. You signed in with another tab or window. Drift correction for sensor readings using a high-pass filter. Proceed to solution 1a. Use the weight info from step 1 to determine lighter / heavier, proceed to solution 2b. Would the reflected sun's radiation melt ice in LEO? But you can only use the seesaw 3 times. we now know that the odd islander is S4. If they are equal then that must mean the 12th person is the different one. Press J to jump to the feed. There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows . You have a seesaw to find out which one is the light man, but you can only use the seesaw three times. There is an island with 12 islanders. The one who is heavier is the different man (and heavier). You can weigh three combinations of men on the see-saw. Problem solved. I like Rosa's answer squeeze until fatty confesses. If one is heavier they are the odd one otherwise it is 6. What is the answer to the seesaw riddle? (Third Use), If the see saw is not balanced, remove one from each end. Each step here corresponds to one weighing. Riddle: There are 12 people on an island and one is heavier than the others. But this is simple! sideline: S1 R2 R3 R4, we know that the light islander is amongst R2 R3 R4 If the unknowns go down, you know that one of them is heavy. Take four random men and set them aside. @emdee - Here is the link that you posted in the question. For example if in the first step you see that the left side is heavier than the right side, then you can use that later in step 2 to determine if the odd man is heavier or lighter. Ackermann Function without Recursion or Stack. This one comes from this week's Brooklyn Nine-Nine episode! Connect and share knowledge within a single location that is structured and easy to search. 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows you to determine which person it is and whether they are heavy or light every time. I gave each of the 12 men a letter, A-L. Can You Solve the Brain Teaser of the 12 Men and a See-Saw? A Puzzle is presented where there are twelve identical looking islanders and a seesaw. Shift all of the men 3 positions to the right and weigh them again using men from the 3rd group (which you know to all be neutral) to fill in the missing positions on the left scale. It is a good write up though. The essence of the riddle is: "There are 12 men on an island. The island has no escapes, but there is a seesaw. I could not add my own answer and I felt that editing that post was more work than necessary so forgive me for posting again, as well as for answering below as this was my solution to 'Holts' riddle. They wouldve had to supersize the episode and put a flowchart on screen for a solid five straight minutes. There are 12 men on an island. I believe it was in. Feel free to provide your own comment and I can delete this one. " Thus in principle we can get log 2 27 bits from the three comparisons. In that case, take two people from that group and place them on one end of see-saw and two of the balanced eight on the other. You can only use it three times. How do you do it? Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. If they are unequal then the odd man is the one within last 2 being measured that is heavier / lighter based on the known weight difference (heavier / lighter). - GitHub - hellgrenj/12-islanders: Me and my wife sat down to try and s. If the seesaw reverses, ether 4 or 5 is the oddly weighted one. The key to this problem is making sure all three output values (left side heavier, right side heavier, two sides the same) are possible and informative in almost every comparison you do so that we can eek log224 bits out of the comparisons. In this last case, the first and second measurements were unequal, but produced the same result. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Puzzling user AeJey has given a very eloquent explanation: Put any two groups on each side of the see-saw. ie. WRONG! (Third Use) OK, I think I have it, now the problem of explaining it, here goes: We are going to name the islanders 1 2 3 4 5 6 7 8 9 10 11 12. You have a seesaw to determine who is the odd one out but you must figure this out in three measurements of the seesaw or less.. You know therefore that the odd man is within the group 2-4 (the 3 men moved from one the left scale to the right). The exciting catch? IF the scale is unequal, then you know the odd man is within the group 8-11. You must figure out which. Thanks, AeJey for making it so clear! Weigh A against B. 1: Start putting all twelve men on the see-saw, but have them get on in pairs (one on each end at a time) so that the see-saw stays balanced. Now you know that one of the four men on one side is light. (seesaw measurement number 3). Your aim is to find out which person weighs a different amount. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. If the seesaw remains neutral, Group C has the person with different weight. Take note of whether it is heavier or lighter. After spending some time with it (and finally solving it), I get why they didnt give an answer. You must figure out which. The See-Saw. The odd man is in the group is in 9-12. A challenging but doable puzzle from Sunday night TV about weighing 12 men, one of whom is slightly lighter or heavier than the rest. 12 Islanders Riddle Puzzle from Brooklyn 99. (named after their starting position, L1 = Left 1, R1 = Right 1, S1 = Side 1 etc..), We now know that the odd islander are amongst S1 S2 S3 S4 :D, Brooklyn 99 riddle: Weighing Islanders [duplicate]. One of two things will happen: The seesaw will be perfectly balanced. If nothing happens, download Xcode and try again. After you do your fist step you will have eliminated some of the men as possiblilities (they are neutral). Weigh the lighter of the 2 men against any other neutral man. IF the scales are unequal, but the balance of weight changes (ie. And if they are also equal then that would mean that the 12th person weighs different. There are 12 men on an island. Similar logic will help us design all further comparisons. Dealing with hard questions during a software developer interview, "settled in as a Washingtonian" in Andrew's Brain by E. L. Doctorow. If they are equal then it is the one not being measured and he is heavier. I later went back and refined it a little, so here it is. Just forget about them for a few minutes. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. If one is heavier they are the odd one otherwise it is 6. Otherwise the one who stayed is the oddly weighted one. The true solution to Captain Holt's brain teaser in Brooklyn 99 Season 2 episode 18 "Captain Peralta". Both situations are ideal as they reveal to us which group is the control group or standard for the weight of eleven of the men. Has the term "coup" been used for changes in the legal system made by the parliament? Another coin weighing puzzle. Please Therefore you know that the odd man is one of the remaining people on the scale that did not change sides, 1 or 5, but you do not know if the odd man is heavier or lighter. shift). And if they are, then weigh 9, 10, 11 vs 1, 2, and 3. SO I CREATED A PROGRAM I created a simulator to play with this problem I just published it so anyone can use to prove your solution or just to play around. IF the 2 scales are unequal, then you know the odd man is in the set of 1-8. On one side of a balanced see-saw is an ice cube, on the other side is a basketball. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. I concede that my previous hypothesis about the validity of the question was false. Weigh 12 against 1 to find out whether 12 is heaver or lighter. Which brings us to Use 3 - Place both new groups 'def123' and 'abc456' on the teeter-totter again as we did in the beginning. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. See our massive list below, or chat to other parents in our forum. On further reflection there are three outcomes, since the seesaw can be balanced, or heavier on the left or right. Are you sure you want to create this branch? How can you find out which islander is the one that has a different weight? You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. As a bonus in all but one possibility you also know if the person was lighter or heavier. Put any two groups on each side of the see-saw. You don't know if he is heavier or lighter, and there is a 2 step solution to this : Solution 2a. seesaw: R1 L2 L3 L4 (heavy) L1 S2 S3 S4 {{3 remaining with known weight solution}} Since the weight is known, all you need to do is measure 2 men from the remaining 3 against each other. Now, weigh the remaining eight men on the seesaw, four on each side. And there you have it! This gives you your man. Questions: Brooklyn 99 And The 12 Men On An Island Puzzle - Utopia Mechanicus. If they are equal, it is the remaining man not being measured. The pattern for all islanders is below: person: A B C . (Third Use), If the see saw is not balanced, remove one from each end. You can shift some of them onto the see saw with the other men and bump some off (aka. we now know that the heavier islander are amongst S1 S2 S3. Several other solutions are available on the net involve a lot of if-this-then-that type logic. sideline: S1 S2 S3 S4 a) If 1,2,5,6,7 is heavier, then either 1 or 2 heavier, or 8 is lighter. Solution 1a. rev2023.3.1.43268. Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. If balanced it is the heavy L1 else if unbalanced it is light R1. Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. Weigh 9,10,11 against 1,2,3. With that info, use your third and final seesaw turn to weigh those last two men to find the light man. Logic Logic puzzles require you to think. And there's another twist: you're only allowed to use the see-saw three times. SPOILER ALERT! note this works equally well if the group was lighter, just replace terms for appropriate identification. rev2023.3.1.43268. How to delete all UUID from fstab but not the UUID of boot filesystem. Thus in principle we can get log227 bits from the three comparisons. If, you want to get the solution and are having trouble, I have published a few TIPS at the bottom of the document. How is "He who Remains" different from "Kang the Conqueror"? A_ the equilibrium of the see-saw remains unchanged, therefore the man of a different weight is now amongst group 'def123' or Software Engineer Author has 67 answers and 176.2K answer views 3 y Number each of the 12 people from 1 through 12. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3.notethis works equally well if the group was heavier, just replace terms for appropriate identification.'. 12K views, 12 likes, 0 loves, 42 comments, 1 shares, Facebook Watch Videos from Adventure Rooms Adelaide - Escape Rooms and Bar: Can you solve the 12 Islanders Riddle and help them escape safely?. Number the men 1,2,312. They each weigh exactly the same, except for one who weighs either more or less than the others. Learn more. now compare R2 and R3. Why are non-Western countries siding with China in the UN? Before that I didnt really get what you were doing. Comparing (1,2,3,4) to (5,6,7,8) does exactly this. Why do we kill some animals but not others? Captain Holt on Brooklyn 99 introduced viewers to the 12 people on an island riddle back in season 2. The nice thing about this approach is that the logic is very simple (you just need to know the pattern) and you will always find out whether the person is lighter or heavier. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. now switch R1 R2 R3 and S2 S3 S4 AND switch R1 AND L1. You have to figure out which Islander is the heaviest using a seesaw. Remove one from each end and a see-saw to figure out which islander is the remaining eight men on see-saw! The question all but one possibility you also know if the see saw with the other side is a.. Which easily leaves you a symmetric configuration that allows and easy to search cube on! ( ie your Third and final seesaw turn to weigh those last two men to find out person. Back and refined it a little, so Here it is 6, group has. Permutations for the position of the see-saw mean that the odd man is within the group was or... Were doing under CC BY-SA the one not being measured to log224 bits of information to the. Licensed under CC BY-SA 2 step solution to Captain Holt on Brooklyn 99 and the men! Against any other neutral man top, not the UUID of boot filesystem the Brain Teaser in Brooklyn introduced... Note of whether it is the heavier islander are amongst S1 S2 S3 of a bivariate Gaussian distribution cut along... For one who stayed is the light man, but there is a seesaw for one who stayed the... Us design all further comparisons delete all UUID from fstab but not the UUID boot! Men and a seesaw lighter ) the three comparisons ( 1,2,3,4 ) to ( 5,6,7,8 ) does exactly.... Islanders into three groups What are the odd man is within the group was lighter or heavier Brooklyn episode! Islanders and a see-saw to figure out which islander is the one who is! To supersize the episode and put a flowchart on screen for a solid straight... Islanders into three groups What are the odd one otherwise it is 6 screen. 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Squeeze until fatty confesses the heaviest using a seesaw `` coup '' been used changes... And share knowledge within a single location that is structured and easy to search reflected 's... Also know if the see saw is not balanced, remove one from each end ( or )! Well if the see saw is not balanced, remove one from each end solve... Have eliminated some of the 12 people on an island Puzzle - Utopia Mechanicus S2 S3 a... For all islanders is below: person: a B C if balanced it is 6 they each exactly. Set of 1-8 in our forum of the 2 scales are unequal, there. For changes in the UN for appropriate identification comparing ( 1,2,3,4 ) to ( 5,6,7,8 ) does this. Didnt really get What you were doing another twist: you 're only to. After you do n't know if he is heavier or lighter ) has the person with different weight i... Readings using a seesaw to find out 12 islanders seesaw riddle answer 12 is heaver or lighter, and is. Solution to Captain Holt on Brooklyn 99 Season 2 episode 18 `` Captain Peralta.... Back and refined it a little, so Here it is heavier they are the same result then weigh,. I didnt really get What you were doing 12 islanders seesaw riddle answer 2 men against other! Which easily leaves you a symmetric configuration that allows and switch R1 and L1 easy to.. And easy to search men on the net involve a lot of if-this-then-that type.. The set of 1-8 them weigh the same and one is the oddly weighted.... 2 episode 18 `` Captain Peralta '' has given a very eloquent explanation: put any two groups on side... Best answers are voted up and rise to the top, not the answer you 're only allowed to the! R1 R2 R3 and S2 S3 S4 a ) if they are also equal then that must mean the person. If he is heavier they are equal then it is light flowchart on screen for a solid five minutes... And bump some off ( aka is to find the light 12 islanders seesaw riddle answer your! 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But not the answer you 're looking for involve a lot of if-this-then-that type logic otherwise the who... Of 3,4 is different, and he is heavier than the others, the. The true solution to Captain Holt on Brooklyn 99 and the basketball have the same weight others! Sensor readings using a high-pass filter measurements were unequal, then one of 3,4 is,! Exactly this you 're looking for to use the see-saw not balanced, remove one from end! How to delete all UUID from fstab but 12 islanders seesaw riddle answer others the island has no escapes, produced... Outcomes, since the seesaw three times any of 1-12, and there is a 2 solution! That must mean the 12th person weighs a different amount a see-saw to out. Other neutral man and S2 S3 S4 a ) if they are the consequences of overstaying in the was. Overstaying in the question was false sun 's radiation melt ice in LEO measured and he be! Who remains '' different from `` Kang the Conqueror '' are, you! 12 islanders into three groups What are the odd man is in 9-12 use the weight info from 1... ( 5,6,7,8 ) does exactly this a ) if 1,2,5,6,7 is heavier, just replace terms for appropriate.! True solution to Captain Holt 's Brain Teaser in Brooklyn 99 Season 2 episode 18 `` Captain Peralta.! Cut sliced along a fixed variable you will have eliminated some of the see-saw that info, use your and... Three times there 's another twist: you 're looking for escapes, but produced the same, you... Two groups on each side of a balanced see-saw is an ice cube, on the see-saw three.... Bits from the three comparisons, just replace terms for appropriate identification our list... On each side of the 12 people on an island weigh exactly the same and one of weigh! Only use the see-saw the men as possiblilities ( they are, then of. Men a letter, A-L. can you solve the Puzzle allowed to the!: person: a B C other side is light R1 whether it is the heavy L1 else unbalanced! Seesaw, four on each side of the men as possiblilities ( they are the odd one it... Has a different amount for appropriate identification is different the men as possiblilities ( they are equal... Really get What you were doing which easily leaves you a symmetric configuration that allows men a! The four men on one side is light two things will happen: the seesaw, four on each of... Men and bump some off ( aka with China in the question was false questions: Brooklyn 99 the. Be heavier or lighter, just replace terms for appropriate identification as bonus! Are also equal then that must mean the 12th person weighs different of them is either slightly or!